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Nonlinear systems — Digital SAT Math practice

A line with a parabola or circle; counting intersections.

Key terms

Common traps

Key ideas to know

Solving Nonlinear Systems

How do you solve a system with one linear equation and one nonlinear equation?

Substitute the linear expression into the nonlinear equation to create a single quadratic, then solve for x and back-substitute to find y.

Watch out: Forgetting to distribute the substitution across all terms in the nonlinear equation or skipping back-substitution.

Counting Intersections with Discriminant

Without solving, how can you determine if a line and a parabola intersect at two points, one point, or no points?

Find the discriminant of the resulting quadratic after substitution. If b2 - 4ac > 0 there are two intersections; = 0 one intersection; < 0 no intersections.

Watch out: Confusing the discriminant sign with the number of solutions or miscalculating a or b when rearranging to standard form.

Contextual Solution Rejection

You solve a system for t and get t = 2 and t = -5. You write the final answer as t = 2, t = -5 without checking constraints. What is wrong?

The error is accepting both roots without applying the context constraint. Since time cannot be negative, reject t = -5 and keep only t = 2.

Watch out: Assuming every algebraic solution is valid regardless of physical constraints or domain limits like square roots or denominators.

Sample questions

Question 1

In the xy-plane, at how many points do the graphs of y = x² − 4 and y = 2x − 1 intersect?

  1. 0
  2. 1
  3. 2
  4. 3
Show answer and explanation

Answer: 2

Set equal: x² − 4 = 2x − 1 → x² − 2x − 3 = 0 → (x − 3)(x + 1) = 0. Two solutions (x = 3, x = −1), so two intersection points.

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