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Math · Advanced Math

Discriminant and number of solutions — Digital SAT Math practice

Use b^2 - 4ac to count real solutions.

Key terms

Common traps

Key ideas to know

Calculating and Interpreting the Discriminant

For the quadratic equation 3x2 - 6x + 4 = 0, what is the discriminant D, and how many real solutions does it have?

D = (-6)2 - 4(3)(4) = 36 - 48 = -12. Since D < 0, there are no real solutions.

Watch out: Students often forget to square b or multiply all three coefficients correctly in 4ac. Always check signs carefully.

Finding Constants for Solution Counts

What value of k makes the equation x2 + kx + 9 = 0 have exactly one real solution?

Set D = 0. So k2 - 36 = 0 → k2 = 36 → k = ±6. Both values give a double root.

Watch out: Forgetting that k2 = 36 yields two possible values, not just one. Always solve completely for squared terms.

Misinterpreting D = 0 Geometrically

A student claims that if a parabola touches the x-axis at exactly one point, the discriminant must be negative. Is this correct? Explain why or why not.

The claim is wrong. Touching the x-axis at one point means D = 0, which gives exactly one real double root, not no real solutions.

Watch out: Confusing D < 0 (no real roots, graph never crosses axis) with D = 0 (one real root, graph just touches the axis).

Sample questions

Question 1

For what value of c does the equation x² + 6x + c = 0 have exactly one real solution?

  1. 3
  2. 6
  3. 9
  4. 36
Show answer and explanation

Answer: 9

Exactly one solution means the discriminant is 0: b² − 4ac = 36 − 4c = 0 → c = 9.

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